3х²-2х-5=0
х = -(-2)±√(-2)²-4×3×(-5) / 2×3
х = 2±√64 / 6
х = 2±8 / 6
х1 = 2+8 / 6
х2 = 2-8 / 6
х1 = 5/3
х2 = -1
A) (c-2)(c+3)-(c-1)²=c²-2c+3c-6-c²+2c-1=3c-7
) 3(a+c)²-6ac=3(a²+2ac+c²)-6ac=3(a²+c²)
B) (p-3)(p²+3p+9)-p³=p³+3p²+9p-3p²-9p-27-p³=-27
А) 6х/ 4у
б) -2х/ -4
Вот и все решение!