A)=<u>x^2-4-x^2-4=</u> -<u> 8
</u> x-2 x-2
б)=<u>(m-n)^2+2*2mn=</u><u>m^2-2mn+n^2+4mn=</u><u>(m^2++2mn+n^2= (m+n)^2 </u>
2mn(m-n) 2mn(m-n) 2mn(m-n) 2mn(m-n)
в) =<u>(p+3)(p-4)-(p-3)(p+4)= </u> <u>p^2-4p+3p-12-p^2-4p+3p+12=</u> <u>-2p </u>
(p-4)(p+4) p^2-16 p^2-16
г) = <u>7pq+q^2-p^2-7pq</u>= <u>q^2-p^2</u>=<u>-(p-q)(p+q)</u>= - <u> p+q.</u>
pq (p-q) pq(p-q) pq(p-q) pq
<u>
</u>
2) 1/2*(2sinπ/12cosπ/12)=1/2*sin2π/12=1/2sinπ/6=1/2*1/2=1/4
3) 2*5sin32/2*cos16*cos(90-74)= 10sin32/2*cos16*sin16=10sin32/sin32=10
4)27cos2a=27*(cjs²a-sin²a)
по формуле sin²a+cos²a=1 найдем sin²a
(1/3)²+sin²a=1 sin²a=1-1/9=8/9
27*(cos²a-sin²a)=27*(1/9-8/9)=27*-7/9=-21
5) =-5(sin(2π-a)+2cos(3π/2+a)=5sina-2sina=3sina=3*(-0.1)=-0.3
B3 = b1*q^2 ==>
b1*q^2 = 64
b1*(1/2)^2 = 64
b1 = 64 / 0.25
b1 = 256
S7 = (b1*(1 - q^7))/(1 - q) = (256*(1 - (1/2)^7))/(1 - (1/2)) = 508
2x-3y=7 17x=17 x=1
15x+3y=10 2x-3y=7 y=1,66