25sin²x + 10cos²x = 13
15sin²x + 10sin²x + 10cos²x = 13
15sin²x + 10(sin²x + cos²x) = 13
sin²x + cos²x = 1
15sin²x + 10 = 13
15sin²x = 13 - 10 = 3
5sin²x = 1
sin²x = 1/5
cos²x = 1 - sin²x = 1 - 1/5 = 4/5
tg²x = sin²x/cos²x = (1/5)/(4/5) = 1/4<span>
tgx₁ = 1/2
tgx₂ = - 1/2
</span><span>
</span>
A(1)=a(21)-2x20=17-40=-23
S(30)=(-23x2+29x2);2x30=-46+58);2x30=6x30=180
Для 3π/2 <α <2π: sin α < 0.
Поэтому sin α = -√(1 - cos²α) = -√(1 - (1/3)²) = -2√2/3.