<span>4 sin^2x cos^2x+4 cos^4x-4 cos^2x+ 1 =</span><span> 4cos^2x(</span><span><span>sin^2x +</span>cos^2x) - 4cos^2x+ 1=
=</span> 4cos^2x <span>- 4cos^2x+ 1=</span> 1
9⁵-9⁴+9³=9·³(9²-9+1)=9³·73 - кратно 73
A) 4x (2x-1)-(x-3)(x+3)= 8x`2-4x-x`2+9=6x`2-4x+9
y = x² + 3x + 2
a) x = - 2
y = (-2)² + 3 * (- 2) + 2 = 4 - 6 + 2 = 0
При x = - 2 , y = 0
б) y = 6
6 = x² + 3x + 2
x² + 3x - 4 = 0
x₁ = - 4 x₂ = 1
При x = - 4 и x = 1 , y = 6
в) y = 0
x² + 3x + 2 = 0
x₁ = - 2 x₂ = - 1
При x = - 2 и x = - 1 значения функции равны нулю .