![f(x)=x^3-4\sqrt x=x^2-4x^{\frac{1}{2}}](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E3-4%5Csqrt%20x%3Dx%5E2-4x%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
![F(x)=\frac{x^{3+1}}{3+1}-4\cdot\frac{x^{\frac{1}{2}+1}}{-\frac{1}{2}+1}+C=](https://tex.z-dn.net/?f=F%28x%29%3D%5Cfrac%7Bx%5E%7B3%2B1%7D%7D%7B3%2B1%7D-4%5Ccdot%5Cfrac%7Bx%5E%7B%5Cfrac%7B1%7D%7B2%7D%2B1%7D%7D%7B-%5Cfrac%7B1%7D%7B2%7D%2B1%7D%2BC%3D)
![\frac{x^{4}}{4}-4\cdot\frac{x^{\frac{3}{2}}}{\frac{3}{2}}+C=](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B4%7D%7D%7B4%7D-4%5Ccdot%5Cfrac%7Bx%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%7D%7B%5Cfrac%7B3%7D%7B2%7D%7D%2BC%3D)
![\frac{x^{4}}{4}-\frac{8x^{\frac{3}{2}}}{3}+C](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B4%7D%7D%7B4%7D-%5Cfrac%7B8x%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%7D%7B3%7D%2BC)
проходит через точку А (4;3)
![F(4)=3](https://tex.z-dn.net/?f=F%284%29%3D3)
![\frac{4^{4}}{4}-\frac{8\cdot4^{\frac{3}{2}}}{3}+C=3](https://tex.z-dn.net/?f=%5Cfrac%7B4%5E%7B4%7D%7D%7B4%7D-%5Cfrac%7B8%5Ccdot4%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%7D%7B3%7D%2BC%3D3)
![4^3-\frac{8\cdot(2^2)^{\frac{3}{2}}}{3}+C=3](https://tex.z-dn.net/?f=4%5E3-%5Cfrac%7B8%5Ccdot%282%5E2%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%7D%7B3%7D%2BC%3D3)
![64-\frac{8\cdot2^3}{3}+C=3](https://tex.z-dn.net/?f=64-%5Cfrac%7B8%5Ccdot2%5E3%7D%7B3%7D%2BC%3D3)
![64-\frac{8\cdot8}{3}+C=3](https://tex.z-dn.net/?f=64-%5Cfrac%7B8%5Ccdot8%7D%7B3%7D%2BC%3D3)
![64-\frac{64}{3}+C=3](https://tex.z-dn.net/?f=64-%5Cfrac%7B64%7D%7B3%7D%2BC%3D3)
![C=3-64+\frac{64}{3}](https://tex.z-dn.net/?f=C%3D3-64%2B%5Cfrac%7B64%7D%7B3%7D)
![C=-61+\frac{64}{3}](https://tex.z-dn.net/?f=C%3D-61%2B%5Cfrac%7B64%7D%7B3%7D)
![C=-\frac{183}{3}+\frac{64}{3}](https://tex.z-dn.net/?f=C%3D-%5Cfrac%7B183%7D%7B3%7D%2B%5Cfrac%7B64%7D%7B3%7D)
![C=-\frac{119}{3}](https://tex.z-dn.net/?f=C%3D-%5Cfrac%7B119%7D%7B3%7D)
![F(x)=\frac{x^{4}}{4}-\frac{8x^{\frac{3}{2}}}{3}-\frac{119}{3}](https://tex.z-dn.net/?f=F%28x%29%3D%5Cfrac%7Bx%5E%7B4%7D%7D%7B4%7D-%5Cfrac%7B8x%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%7D%7B3%7D-%5Cfrac%7B119%7D%7B3%7D)
Обозначим ширину Хсм. Тогда периметр будет (9,8+Х)х2. Длина составляет 35% от периметра. Получаем уравнение
9.8=0.35х(9.8+Х)х2
9.8=6,86+0.7Х
Х=4,2 см
Площадь 4,2х9,8=41,16 см2
Ответ:41,16 см2
а)20х в4 у в2-35х в3 у в2=5ху в2(4х в3-7х в2)
б)-3ав в2 с+9ав в2 с в3=3ав в2 с(-а в2+3с в2)