f(x)=3sinx+2cos x
f(x)=(3sinx+2cosx)=3cosx-2sinx
первую производную = к нулю
f(x)=0
3cosx-2sinx=0 / :cosx≠0
-2tgx=-3
2tgx=3
tgx=3/2
Chislitelni ravni⇒znamenatelni toje ravni,( pri etom 4x+1≠0⇒x≠-1/4)⇒
4x+1=8⇒4x=8-1⇒4x=7⇒x=7/4
А. 25+(16+74) = 25 + 90 = 115
б. 37*6 - 29*5 = 222 - 145 = 77
в. (86-17)(86+17) = 9 * 103 = 927
г. 98 : (9+5) = 98 : 14 = 7
(2x-3)^3 - (2x-3)^2=12x-18