Question

Нужна помощь в решении
a005

Answer 1

$1)3 \frac{1}{3}+2,5= \frac{10}{3}+ \frac{5}{2}= \frac{35}{6} \\ \\ 2)2,5-1 \frac{1}{3}= \frac{5}{2}- \frac{4}{3}= \frac{7}{6} \\ \\ 3) \frac{35}{6}: \frac{7}{6}=5 \\ \\ 4)4,6-2 \frac{1}{3}= \frac{23}{5}- \frac{7}{3}= \frac{69-35}{15}= \frac{34}{15} \\ \\ 5) 4,6+2 \frac{1}{3}= \frac{23}{5}+ \frac{7}{3}= \frac{69+35}{15}= \frac{104}{15} \\ \\ 6) \frac{34}{15}: \frac{104}{15} =\frac{34}{104}= \frac{17}{52}$

$7)5\cdot \frac{17}{52}\cdot5,2=8,5 \\ \\ 8) \frac{1}{7}-0,125 =\frac{1}{7}- \frac{1}{8}= \frac{1}{56} \\ \\ 9)0,05: \frac{1}{56}= \frac{1}{2}: \frac{1}{56}=28 \\ \\ 10)28+5,7=33,7 \\ \\ 11) 8,5:33,7=2 \frac{186}{337}$