1) 2cox = √3
cosx = √3/2
x = +- arccos(√3/2) + 2πk, k ∈ Z
x = +- π/6 + 2πk
2)sin x = 1/2
x = (-1)^k arcsin(1/2) + πk, k ∈ Z
x = (-1)^k π/6 + πk
3)cos2x = -1
2x = π + 2πk, k ∈ Z
x = π/2 + πk
512a^16*4096a^16=209408a^22.
0,6mn−3n; 0,5tu−0,5u <span>b−bt</span>