T + 1/t = 13/6 | ·6t≠0
6 t² + 6 -13 t= 0
6t² -13 t +6 = 0
t1 = 3/2 t2 = 2/3
1) t = 3/2
x/у = 3/2 ⇒ 2х = 3у ⇒ 2(5 -у) = 3у⇒10 -2у = 3у ⇒ 10 = 5у⇒<em>у = 2</em>
х +у = 5 ⇒ х = (5 -у)
<em>х = 5-у = 5 - 2 = 3</em>
<em>(3;2)</em>
2) t = 2/3
х/у = 2/3 ⇒3х = 2у ⇒3(5-у) = 2у⇒15 -3у = 2у ⇒ 15 = 5у ⇒<em> у = 3</em>
х + у = 5⇒х = (5 -у)
<em>х = 5 - у = 5 - 3 = 2</em>
<em>(2;3)</em>
∠BCD опирается на диаметр BD.
∠BCD=90°,
∠ABD=ACD=32° как углы опирающиеся на одну и ту же дугу
∠BCM=90°-∠ACD=90°-32°=58°
Cумма углов треугольника ВМС равна 180°.
∠ВМС=180°-∠МВС-∠ВСМ=180°-64°-58°=58°
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Ответ:<em> </em><em>1</em>
1.
a0<span> = 1 (</span>a<span> ≠ 0)</span>
2.
a1<span> = </span>a
3.
<span>an</span><span> · </span><span>am</span><span> = </span>a<span>n + m</span>
4. (
<span>an</span>)m<span> = </span><span>anm</span>
5.
<span>an</span><span>bn</span><span> = (</span>ab)n
<span><span><span>6. <span>a-n</span> = </span>1</span><span>an</span></span>
<span><span>7. <span>an</span><span> = <span>an - m</span></span></span><span>am</span></span>
8.
a<span>1/n</span><span> = </span>n√<span>a</span>