Question

V(t) = 3t^2+1 t=0S=0,5S(t)-?

Answer 1

$v(t)=3t^2+1$
$s(t)=\int v(t) dx=t^3+t+C$
$s(0)=0.5$
$0^3+0+C=0.5$
$C=0.5$
$s(t)=t^3+t+C$