√(60)/√(5)*2*√(3)=<span>√(60/5)*√(4*3)=</span><span>√(12)*√(12)=</span><span>√(12*12)=</span><span>12</span>
Sin(x)+sin(x)=<span>√3
2sin(x)=</span><span>√3
sin(x)=</span><span>√3/2
x=(-1)^k*pi/3+pi*n, n пренадлежит Z</span>
<span>1,96-у2=0
-y2+1,96=0
y2-1,96=0
y2=1,96
y= -1,4
у=1,4
Ответ: -1,4; 1,4</span>