Если так 4^-5×(4^2÷4^-4)
то будет 4
1) 5х-21+7х=2х+11
10х=32
Х=3,2
2) 6х-3,2=7х-6х+7,5
5х=10,7
Х=2,14
3) 10-2х-10х+15=1
2х=14
Х=7
4) 44-30+40х=35х+14
5х=0
Х=0
5) 0,3-2х-2=0,4х+0,1
2,4х=-1,8
Х=0,75
Метод Лягерра, точность <span> 1e-3</span>
<span>x1 ≈ 0.666666552553487
<span>P(x1) ≈ 0 <span>iter = </span>4
</span><span>x2<span> ≈ 0.749999727053003 − i ∙ 0.66143770861557
</span>P(x2) ≈ 0 <span>iter = </span>3
</span><span>x3<span> ≈ 0.750000123124048 + i ∙ 0.661438012106969
</span>P(x3) ≈ 0 <span>iter = </span>3
</span><span>x4<span> ≈ 1.0000003286761
</span>P(x4) ≈ 0 <span>iter = </span>1
</span><span>x5<span> ≈ 1.49999993526003
</span>P(x5) ≈ 0 <span>iter = </span>1</span></span>