Question

Сократите дробь: x^5+2x^4-9x-18/(x^2+3)*(x^2-x-6)

Answer 1

$\frac{ x^{5}+2 x^{4}-9x -18}{( x^{2}+3)*( x^{2}-x-6)}= \frac{ x^{5}-9x+2x^{4} -18}{( x^{2}+3)*( x^{2}-x-6)}=\frac{ x*(x^{4}-9)+2(x^{4} -9)}{( x^{2}+3)*( x^{2}-x-6)}= =\frac{( x+2)*(x^{2}+3)*(x^{2}-3)}{( x^{2}+3)*( x^{2}-x-6)}=\frac{( x+2)*(x^{2} -3)}{( x^{2}-x-6)}$
вроде так