1\4 700 г
3\4 2100 г
2\7 800 г
5\7 2000 г
Δy=y(x₀+Δx)-y( x₀)=5-2(x₀+Δx) - (5-2x₀)=5-2x₀-2Δx-5+2x₀=-2Δx=-2·0,4=-0,8
1)-1/8a^2+1/4ab-1/8b^2=-1/8* (a²-2ab+b²)=-1/8 *(a-b)(a-b)
2)3a(b-4)-2b+8=3a(b-4)-2(b-4)=(b-4)(3a-2)
<span>3)x^3+3x^2-x-3=x</span>²(x+3)-(x+3)=(x+3)(x²-1)=(x+3)(x+1)(x-1)
Cos(arccos(a))=a, a∈[-1;1]