D=(60,6-61,8)/3=-0,4
a4=a1-0,4(n-1)
61,8=a1-1,2
a1=63
S7=n(a1-0,4(n-1))/2
S7=7*(63-2,4)/2
S7=212,1
5^x-√(3x-5)<125
x-√(3x-5)<3
x-3<√(3x-5)
ОДЗ 3x-5≥0⇒x≥5/3
(x-3)²<(√(3x-5)²
x²-6x+9<3x-5
x²-9x+14<0
x1+x2=9 U x1*x2=14
x1=2 U x2=7
/////////////////////
----[5/3]----------(2)------------(7)-----------
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
x∈(2;7)
За разъяснениями обращаться в чат
-40+2x=10x+20
8x=-60
X=-7 4/60
X=-7 2/30