Sполной поверхности=2πR(R+h)=0.1π(0.05+8)=0.805π
Sбоковой поверхности=2πRh=0.8π
Log_5(2x+3) + log_5(4-x) = 1 ОДЗ: x>-1,5
log_5(2x+3)*(4-x) = log_5(5) x<4
(2x+3)(4-x) = 5 x <span>∈ (-1,5;4)</span>
8x - 2x^2 + 12 - 3x - 5 = 0
-2x^2 + 5x +7 = 0 |*(-1)
2x^2 -5x - 7 = 0
x1 = 7, x2 = -2 - не удовлетворяет ОДЗ
Ответ: x = 7
79+4/|x|=81,8
4/|x|=81,8-79
4/|x|= 2,8
4/2,8=|x|
4/28/10=|x|
4/14/5=|x|
2/7/5=|x|
2×5/7=|x|
10/7=|x|
|x|=10/7
x1= 10/7
x2=-10/7
X + 4 = (-1)
x = (-1) - 4
x = (-5)
5 - x = 10
x = 10 - 5
x = 5
x - 7 = (-10)
x = (-10) + 7
x = (-3)
x - (-4) = 0
x + 4 = 0
x = (-4)