Question

Помогите решить 347 номер

Answer 1

$\frac{1}{2} + \frac{1}{3} = \frac{3+5}{6} = \frac{5}{6} \\ \frac{2}{3}+ \frac{1}{4}= \frac{4*2+3}{12} = \frac{11}{12} \\ \frac{5}{7}- \frac{1}{6} = \frac{6*5-7}{42} = \frac{23}{42} \\ \frac{1}{8}+ \frac{1}{4}= \frac{2+4}{16} = \frac{6}{16} \\ \frac{1}{4}+ \frac{2}{5}= \frac{5+2*4}{20} = \frac{13}{20} \\ \frac{3}{4}+ \frac{2}{5}= \frac{3*5+2*4}{20} = \frac{23}{20} \\ \frac{3}{4} - \frac{1}{3} = \frac{3*3-4}{12} = \frac{5}{12} \\ \frac{2}{3}- \frac{5}{9}= \frac{2*3-5}{9} = \frac{1}{9}$

Answer 2

А)3/6 + 2/6=5/6
в)8/12 + 3/12 = 11/12
д)30/42 - 7/42=23/42
ж)1/8 + 2/8=3/8
б)3/12 + 8/12=11/12
г)15/20 + 8\20=23/20
е)9/12 - 4/12=5\12
з)6/9 - 5/9=1/9