<span><span>NaOH</span>+<span>HCl</span> → <span>NaCl</span>+<span>H2<span>O
</span></span></span><span><span>2<span>NaOH</span></span>+<span>CO2</span> → <span>Na2CO3</span>+<span>H2<span>O
</span></span></span>
Где рисунок ?!!!!!!!!!!!!
Дано: W(O)=42.67%
формула :CnH2n(NH2)COOH
Решение:
0.4267=32/14n+61)
n=1
NH2CH2COOH-аминоуксусная
K2O+2HCl=2KCl+H2O реакция обмена