1)b1=1/6, q=1/3
b3=b1.q², b3=1/6. (1/3)²=1/6.1/9=1/54, b3=1/54
2)b1=-6, q=3
b3=-6.3²=-6.9=-54, b3=-54
3)b1=4,q=2
b3=4.2²=4.4=16, b3=16
АОВ=140*
АОС=110*
АОD=160*
BOC=30*
BOD=120*
COD=90*
X^2-6x+p=0
-4^2-6*(-4)+p=0
16-(-24)+p=0
40+p=0
p=-40
Х<span>² - 6х - 16 = 0
(х-3)</span><span>² - 25 = 0
(х-3)</span>² - 5<span>² = 0
(х-3-5)(х-3+5) = 0
(х-8)(х+2) = 0
</span>
= 8;
= -2
<span>Ответ: -2; 8</span>
По формуле Sn=(b1*(q^n-1))/(q-1)
330=(b1*(-2^5-1))/(-2-1)
330=(b1*-33)/-3
330=b1*11
b1=30