Дано
m(Co)=5.9 g
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V(SO2)-?
Co+2H2SO4(k)-->CoSO4+SO2↑+2H2O
M(Co)=59 g/mol
n(Co)=m/M=5.9/59=0.1 mol
n(Co) = n(SO2)=0.1 mol
V(SO2) = n(SO2)*Vm = 0.1*22.4=2.224 L
ответ 2.24 л
D(возд)=M/29
M=1,862*29=54г/моль
w=n*Ar*100%/Mr
n=w*Mr/Ar*100%
n(C)=87.98*54/12*100=4
w(H)=100-87,98=12,02%
n(H)=12,02*54/100=6
Ответ: C4H6
Zn + 2HCl = ZnCl₂ + H₂
m(HCl)/[2M(HCl)]=V(H₂)/V₀
m(HCl)=2M(HCl)V(H₂)/V₀
m(HCl)=2*36,5г/моль*67,2л/(22,4л/моль) = 219 г (ответ)