(x-1)^2*(x^2+4x-12)<0
(x-1)^2*(x^2+4x-12)=0
(x-1)^2=0 или x^2+4x-12=0
для 1: x(1)=1
для 2: x(2)=2
x(3)=-6
Подстановка:
-7: (-7-1)^2*(-7^2-7*4-12)=64*12>0
0: (0-1)^2*(-12)<0
1,5: (1,5-1)^2*(1,5^2+1,5*4-12)<0
3: (3-1)^2*(3^2+3*4-12)>0
Ответ: -6<x<1 и 1<x<2
1/16; 0.25; 1 ; ...
b1*b2*b3*b4*b5*b6*b7 = b1* b1q*b1q^2*b1q^3*b1q^4*b1q^5*b1q^6=b1^7*q^21=(b1q^3)^7=(b4)^7
b4=b3q
q=b3/b2=1/0.25=4
b4=1*4=4
(b4)^7 = 16384
X²(x-3)-4(x-3)=0
(x-3)(x²-4)=0
x-3=0⇒x=3
x²-4=0⇒x²=4⇒x=-2 U x=2