Вот решение. Это деление окружности на шесть равных частей
X + 2/3x = 45
5/3x = 45
x = 45 * 3/5 = 9 * 3 = 27
2/3x = 27 * 2/3 = 18
18 + 27 = 45
<span>int(sin^3(4x/5)*dx)=int(sin4x/5 *sin^2(4x/5)*dx)=-5/4*int(-4/5*sin(4x/5)*dx*(1-cos^2(4x/5)))=-5/4*int( (1-cos^2(4x/5)*d(cos(4x/5))=-5/4*(cos(4x/5)-1/3*cos^3(4x/5))+C=5/12 *cos^3(4x/5)-5/4 *cos(4x/5)+C</span>
X+3 7/9=6 5/6
x= 6 5/6-3 7/9
x=3 (5/6-7/9)
x=3 (15/18-14/18)
x=3 1/18