Question

Y=корень(3х-7)(х+2) Дробь Х+3

Answer 1

$Y= \frac{\sqrt{(3x-7)(x+2)} }{x+3}\\ (3x-7)(x+2) \geq 0\\ (3x-7)(x+2)=0\\ 3x^{2}+2-7x+2=0\\ 3x^{2}-7x+4=0\\ D=b^{2}-4ac=49-48=1 \sqrt {D}=\sqrt{1}\\ x_{1}= \frac{-b+\sqrt{D}}{2a} = \frac{7+1}{6}= \frac{8}{6} \\ x_{2}= \frac{-b-\sqrt{D}}{2a} = \frac{7-1}{6}=1\\ x \neq -3$