СH3 - CH - CH2 - CH - CH - CH2 - CH3
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CH3 CH3 CH2
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CH3
H2
n(H2) = 1/22.4=0.04моль
m(H2) = 0.04*2=0.08г.
<span><span>дано:
</span>Li₂SO₄<span>
найти: w(Li),w(S), w(O)
решение:
Mr(Li</span>₂SO₄<span>) =
1*2 + 32 +16*4 = 110
w(э) = Ar(э)*n(э)\Mr(в-ва)
w(Li) = 7*2\110 = 0,1272 или 12,72%
w(S) = 32*1\110 = 0,2909 или 29,09%
w(O) = 16*4\110 = 0,5818 или 58,18%
ответ:<span>w(Li) = 12,72%, w(S) = 29,09%,<span> w(O) = 58,18%</span></span></span></span>
1)K2SO3 + 2HCl => KCl + SO2 + H2O
2)2SO2 + O2 => 2SO3
3)SO3 + Ba(OH)2 => BaSO4 + H2O
Реакция горения:
2СН=СН2+5О2=4СО2+2Н2О