4CH3NH2 + 9O2 => 4CO2 + 10H2O +2N2
4C6H5NH2 + 31O2 => 24CO2 + 14H2O + 2N2
1) Na2S
Mr(Na2S) = 23*2+32 = 78
w(S) = 32/78 = 0.41 = 41%
Na2SO3
Mr(Na2SO3) = 23*2+32+16*3 = 126
w(S) = 32/126 = 0.253 = 25.3%
H2S
Mr(H2S)= 1*2+32=34
w(S) = 32/34= 0.941=94.1%
следовательно, минимальная массовая доля серы в Na2SO3
2) <span>S+H2->H2S </span>
<span>2H2S+3O2(избыток)->2H2O+2SO2 </span>
<span>SO2+2NaOH->Na2SO3+H2O </span>
1. 4Li+O2=2Li2O
2. 2KClO3=2KCl=3O2
2O2+3Fe=Fe3O4
3. -