(3-2i)/(1+3i)=(3-2i)(1-3i)/(1+3i)(1-3i)=(3-2i-9i+6i²)/(1-9i²)=
=(3-11i-6)/(1+9)=(-3-11i)/10=-0,3-1,1i
<span>3 2/7+5 5/7-1 5/9-2 8/9=4 5/9
1)</span>3 2/7+5 5/7=9
2)9<span>-1 5/9=7 4/9
3)</span>7 4/9<span>-2 8/9=4 5/9</span>
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(4 3/4 - 1 2/9*2 1/2)*1 3/5=(3 19/36 - 1 2/9*2 1/2)*1 3/5=(3 19/36 - 3 1/18)*1 3/5=17/36*1 3/5=34/45
Решение задания приложено