Question

Решите систему {3x^2+y=6 {4x^2-y=1

Answer 1

$\left \{ {{3x^2+y=6} \atop {4x^2-y=1}} \right. \; \oplus \; \left \{ {{3x^2+y=6} \atop {7x^2=7}} \right. \; \left \{ {{3x^2+y=6} \atop {x^2=1}} \right. \; \left \{ {{y=6-3x^2} \atop {x^2=1}} \right. \; \left \{ {{y=3} \atop {x=\pm 1}} \right. \\\\Otvet:\quad (-1,3)\; ,\; (1,3)\; .$