,,,,,,,,,,,,,,,,,,,,,,,,,
.....21.2.....................................x.
Na2CO3 + CaCl2 = 2NaCl + CaCO3
106.......................................100
21.2-x
106-100
X= 21.2×100/106=20
Как то так
Дано
V(C4H8)=3.36 L
HCL
------------------------
m(C4H9CL)-?
3.36 X
H2C=CH-CH2-CH3+HCL-->CH3CL-CH2-CH2-CH3
22.4 92.5
Vm=22.4 L/mol M(C4H9CL)=92.5 g/mol
X=3.36*92.5 / 22.4
X=13.875 g
ответ 13.875 г