5^4*0.2^-2/125^2=1
1)5^4=625
Х(3х-1)=0
х=0 или. 3х-1=0
х=1/3
ответ: 0; 1/3
А) (х2-7х+6) /( 36-12х+х2)=(x-6)(x-1)/(x-6)²=(x-1)/(x-6)
x²-7x+6=0
x2+x2=7 U x1*x2=6⇒x1=6 U x2=1
<span>б) [(а+1)3 + (2а-3)3] / [3(3а3-2а2) - 9(3а2-2а)+39а-26]=
=(a</span>³+3a²+3a+1+8a³-36a²+54a-27)/(9a³-6a²-27a²+18a+39a-26)=
=(9a³-33a²+57a-26)/(9a³-33a²+57a-26)=1
1)-6,5*(-320)=2080
2)1035= (3^2) *5*23
3)k=d:6 и k=6:d
4)-85-а+3-3а-3-6-8+а=-99-3а
5)15,7114=х0,25 => 62,8456
6)15х+8=17-120х
15х+120х=17-8
135х=9
х=1/15