Question

Sin(п/2)- cos(3п/2)+cosП- tg0+ctg 2 (3п/2)

Answer 1

$\sin( \frac{\pi}{2} )-\cos(\frac{3\pi}{2} )+\cos \pi -tg0+ctg^2\frac{3\pi}{2} =1-0-1-0+0=0$