Question

Помогите найти первообразную: 1)у=4х^11-2x+4x^5-6 2)y=(12-5x)^5 3)y=cos (16x-2)

Answer 1

$1) y=4x^{11}-2x+4x^{5}-6 \\ F(x) = \frac {x^{12}}{3}-x^2+\frac {2x^6}{3}-6x\\ 2) y=(12-5x)^5 \\ F(x)= -\frac {(12-5x)^6}{5*6} \\ 3) y= cos(16x-2) \\ F(x) = \int cos(16x-2) \ dx - C= - \frac {1}{16} sin(2-16x) + C - C$