2,3xy²-3,1xy²-1,2xy² и 0,27bc³+0,4bc³-0,66bc³ = -2xy²
0,27bc³+0,4bc³-0,66bc³ = 0,01bc³
4x^2(x+3) -3(x+3)=0
<span>(4x^2-3)(x+3)=0 </span>
<span>Ответ: </span>
<span>х1 = -корень(3)/2 </span>
<span>х2 = корень(3)/2 </span>
<span>х3 = -3</span>
3t+5/4=5t+1/3
3t-5t=1/3-5/4
3t-5t=4/12-15/12
-2t=-11/12
t=11/6
t=1 целая 5/6
5x+3/5=x-5/8
5x-x=-5/8-3/5
4x=-25/40-24/40
4x=-49/40
x=-49/10
x=-4.9
(1/3*1/2m+1/3*(-3)-m*1/2m-m*(-3)
(1/3*1/2m+1*(-1)-m*1/2m-m*(-3)
(m/2*3+1*(-1)-m*1/2m-m*(-3)
1/6m+1*(-a)-m=1/2m-m*(-3)
(1/6m-1-m*1/2m-m*(-3)
(1/6m-1-1/2m^2-m*(-3)
(1/6m-1-1/2m^2+3m)
(-1/2m^2+1/6m+3m-1)
(-1/2m^2+1/6m+3m*6/6-1)
(-1/2m^2+1/6m+18m/6-1)
(-1/2m^2+1/6(m+18m)-1)
(-1/2m^2+19m/6-1)
-1/2m^2+19m/6-1 ответ!