2х²-4ху²+3ху-6у³=2x(x-2y²)+3y(x-2y²)=(2x+3y)(x-2y²)
При <span>х=1/4,у=1/6
</span>(2*1/4+3*1/6)(1/4-2*(1/6)²)=(1/2+1/2)(1/4-2/36)=1*7/36=7/36
вроде так
1 - (2y-3)(y+2)
1 + ( - 2y + 3 )(y+2) = 1 - 2y^2 - 4y + 3y + 6 = 7 - 2y^2- y= - 2y^2 - y + 7 => Ответ: а
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