Решение во вложении.............
37) 26-4х=28-2х
-2х=2
х=-1
9a²+6a+1-4b²=(3a+1)²-(2b)²=(3a+1-2b)(3a+1+2b)
25a²-(4b²-4b+1)=(5a)²-(2b-1)²=(5a-2b+1)(5a+2b-1)
<span>(bn)-геометрическая прогрессия</span>
Z₁ =2+5i ;
z₂ =3+i ;
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z₁+ z₂ =(2+5i) +(3+i) =(2+3) +(5+1)i =5 +6i.
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z₁- z₂ =(2+5i) -(3+i) =(2-3) +(5-1)i = -1 +4 i.
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z₁* z₂ =(2+5i)*(3+i) =6 +2i +15i +5i² =6+17i +5*(-1) =1+17i. * * *i =√(-1) ⇒ i² = -1 * * *
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z₁* z₂ =(2+5i)/(3+i) =(2+5i)*(3-i)/( (3+i)*(3-i)) =(6-2i +15i -5i²)/(3² -i²) =(11+13i)/10 =
11/10 +(13/10) i .