<span>Ba(NO3)2</span><span> + </span><span>H2SO4</span><span>→ </span><span>BaSO4</span>↓ + 2<span>HNO<span>3
M(H2SO4) =98 г/моль
n(H2SO4) =n(BaSO4) = 196/98 =2 моль
M(BaSO4) =233 г/моль
m (BaSO4) = 233*2= 466 г</span></span>
N= m/M = 6 г / 2 г/моль = 3 моль
V=Vm*n=22.4 л/моль * 3 моль= 67.2 л
Дано
V(CH4) = 56 дм3
Решение
n(CH4) = V(CH4) / Vm = 56 / 22.4 = 2.5 моль
N(CH4) = n(CH4) * Na = 2.5 * 6.02 * 10^23 = 15.05 * 10^23 = 1.505 * 10^24
N(C) = 1N(CH4) = 1 * 1.505 * 10^24 = 1.505 * 10^24
N(H) = 4N(CH4) = 4 * 1.505 * 10^24 = 6.02 * 10^24
Ответ:
N(C) = 1.505 * 10^24
N(H) = 6.02 * 10^24