Question

Пожалуйста с полным решением)))

Answer 1

Log(27) 8=log(3^3) (2^3)=1/3 *(3log(3) 2=log(3) 2=log(7) 2 /log(7) 3;
log(3) 7=log(2) 7/log(2) 3;
7^log(27) 8  :  2^log(3) 7=7^( (log(7) 2 /log(7) 3)  :2^(log(2) 7/log(2) 3)=(7^log(7) 2)^(1/log(7) 3)  :(2^log(2) 7)^(1/log(2) 3)=2^(1/log(7) 3) : 7^(1/log(2) 3=2^(1:(log(2)3/log(2)7)) :7^(1:(log(7) 3/log(7) 2))=2^(log(2) 7/log(2) 3) : 7^(log(7) 2 / log(7) 3)=7^(1/log(2) 3 ) : 2^(1/log(7)3)=7^(log(7) 2/log(7) 3) :2^(log(2) 7 /log(2)3)=2^(1/log(7)3) : 7^(1/log(2) 3)=
=2^log(3) 7  :  7^(log(7) 2/log(7)3)=2^log(3) 7 :2^(1/log(7) 3=2^log(3) 7 :2^log(3)7=1