Question

Помогите пожалуйста решить:
a) A:=round(10*2 div 2 mod 5 / 3) - trunc (sqrt(4))
b) M:=succ(round (15 / 2) -pred (13))
c) Y:=round(13.99) mod 5+ trunc(sqrt(121))-125 div trunc(100/8)

Answer 1

A) A:=round(10*2 div 2 mod 5 / 3) - trunc (sqrt(4))=
round(20 div 2 mod 5/3)-trunc(2)=round(10 mod 5/3)-2=round(0/3)-2=-2 
b) M:=succ(round (15 / 2) -pred (13))=suncc(round(7.5)-12)=succ(8-12)=suncc(-4)=-3
c) Y:=round(13.99) mod 5+ trunc(sqrt(121))-125 div trunc(100/8)=
14 mod 5+trunc(11)-125 div trunc(12.5)=4+11-125 div 12=15-10=5