Question

Решите неравенство (x-3)²≤ (x-4)²

Answer 1

$(x-3)^{2} \leq (x-4)^{2} \\ } (x-4)^{2}-(x-3)^{2} \geq 0 \\ (x-4-x+3)(x-4+x-3) \geq 0 \\ -(2x-7) \geq 0 \\ 2x-7 \leq 0 \\ x \leq 3,5 \\ x\in(\infty; 3,5]$

Answer 2

X²-6x+9≤x²-8x+16
x²-6x-x²+8x≤16-9
2x≤7
x≤3,5
x∈(-∞;3,5]