n(CaO)=5,6:56=0,1; n(C)=5,4:12=0,45;
m(C)избытка=(0,45-0,1)x12=4,2гр.
m(CaC2)=0,1x64=6,4;
w(C)=4,2:(4,2+6,4)=0,4(40%);
W(CaC2)=6,4:10,6=0,6(60%).
1.