<span><span>NaCl</span>+<span>H2O</span> → <span>NaOH</span>+<span>HCl
</span></span><span><span>Na2O</span>+<span>H2O</span> → <span>2<span>NaOH</span></span></span><span><span>2
<span>Na</span></span>+<span>2<span>H2O</span></span> → <span>2<span>NaOH</span></span>+<span>H<span>2</span></span></span>
1)
C6H5Br + NaOH = C6H5OH + NaBr
M(C6H5Br)=157г/моль
M(NaOH)=40г/моль
n(C6H5Br)=23.55/157=0.15моль
n(NaOH)=13.5/40=0.3375моль
тк бромбензол в недостатке, считаем по нему:
n(C6H5OH)=0.15моль
M(C6H5OH)=94г/моль
m(C6H5OH)=M*n=94*0.15=14.1г
2)
C6H5Br + NaOH = C6H5OH + NaBr
M(C6H5Br)=157г/моль
n(C6H5Br)=62.8/157=0.4моль => n(C6H5OH)=0.4моль
M(C6H5OH)=94г/моль
m(C6H6OH)теор.=M*n=94*0.4=37.6г
w=30.08/37.6*100%=80%
Ответ:
Объяснение:
1) 4NH3+3O2 -> 2N2 + 6H2O
N2 + O2 = 2NO (t=3000)
2NO+O2 = 2NO2
2NO2 + H2O= HNO3 + HNO2
HNO3 + NaOH = NaNO3 + H2O
2NaNO3 = 2NaNO2 + O2 (t)
2) KNO3 + H2SO4(конц) = HNO3 + KHSO4
2HNO3 + CuO =Cu(NO3)2 + H2O
2Cu(NO3)2 = 2CuO + 4NO2 + O2
2NO2+2C = 2CO2 + N2
Fe+H2SO4-->FeSO4+H2↑
4Zn+10NHO3-->4Zn(NO3)2+N2O+5H20
2Al+6HCl-->2AlCl3+3H2↑