Question

Решите пожалуйста очень срочно!!!!

Answer 1

$\frac{25a^2(b-1)}{3^2d}: \frac{5cd^3}{27ab}: \frac{5a^3(1-b)}{3c^3d^4}=\frac{25a^2(b-1)}{9d}* \frac{27ab}{5cd^3}* \frac{3c^3d^4}{5a^3(1-b)}=$$\frac{25*81a^3bc^3d^4(b-1)}{25*9a^3cd^4(1-b)}=-9bc^2$