Question

= 9$3^{(\sqrt{-x})}$$\sqrt{3}$

Answer 1

${3}^{ \sqrt{ - x} } = 9 \sqrt{3} \\ odz \\ - x \geqslant 0 \\ x \leqslant 0\\ {3}^{ \sqrt{ - x} } = {3}^{2} \times {3}^{ \frac{1}{2} } \\ {3}^{ \sqrt{ - x} } = 3 {}^{ \frac{5}{2} } \\ \\ \sqrt{ - x} = \frac{5}{2} \\ - x = \frac{25}{4} \\ x = - \frac{25}{4}$

Answer 2

Решение на фотографии