1) b=2*2*7*2*3*3= 504, 30=2*3*5, НОД(504,30)=2*3= 6
2) из первого А={4, 5, 6, 7}, из второго В={6, 7, 8, ...},
А/\В= {6,7}
(125 * 2304) + (653 * 1000) - (851 * 106) = 850 794
457 100 + (1423 * (6123 - 5941)) - ((11 007 - 8018) * 3) = 707 119
(382 * 905) + (618 * 905) - (749 * 709) + (251 * 70) = 391 529
<span><span>1027*378-72:36*905-628:4=</span>386239</span>
740-(240+60)=440
(840-40) / 8=100
(66-6)(9+1)=600
(120-20)+4 x 5=120
500 / (100 x 5)=1
300 / (10/ 10)=300