Question

Х^2 × (3х + 1) - (х^2 + 1)^2 = 3

Answer 1

X^2×(3x+1)-(x^2+1)^2= 3
4x^2+x^2-x^4-1=3
5x^2-x^4-4=0
x^2×(5x-x^2-4)=0
x^2=0
x1=0
5x-x^2-4=0
D=b^2-4ac
D=5^2-4×(-1)×(-4)=9
x2,3= -b±√D/2a
x2,3= -5±3/-2
x2=1
x3=4