Question

Помогите решить пункт В

Answer 1

$\\\frac{2-(sin^2\alpha+cos^2\alpha)}{3(sin^2\alpha+cos^2\alpha)}=\frac{2-1}{3}=\frac13$

Answer 2

$\frac{2-sin ^{2} a-cos ^{2} a}{3sin^{2} a+3cos^{2} a} = \frac{1}{3}$