Log3(log4(log²3(x-3)))=0,
О.Д.З. х-3>0, x>3,
log3(log4(log²3(x-3)))=log3(1),
log4(log3²(x-3))=1,
log4(log²3(x-3))=log4(4),
log²3(x-3)=4,
log3(x-3)=±2
1)log3(x-3)=2 2)log3(x-3)=-2
log3(x-3)=log3(9) log3(x-3)=log3(1/9)
x-3=9 x-3=1/9
x=12 x=28/9
Y ' = 12x^3 - 12x^2
y ' = 0
12x^3 - 12x^2 = 0
x^3 - x^2 = 0
x^2 (x - 1) = 0
x = 0 ;
x = 1 ;
+ - +
------- 0 --------- 1 -------> x
f max = y(0) = - 6
f min = y(1) = - 7
Ответ:
Пошаговое объяснение:
-----------------------------------