Question

Lim x->-2 x^4 - 16 / x+2 lim x->1 x^2 - 1 / √x (- 1)

Answer 1

$\lim_{x\to \ -2} \frac{x^4-16}{x+2} = \lim_{x\to \ -2} \frac{(x^2-4)(x^2+4)}{x+2} = \lim_{x\to \ -2} \frac{(x-2)(x+2)(x^2+4)}{x+2} =$-32