Question

10 - у /6 + 3 у +8 /3 = у+6 /2

Answer 1

$\frac{10-y}{6} + \frac{3y+8}{3} = \frac{y+6}{2}$
$\frac{10-y}{6} + \frac{3y+8}{3} - \frac{y+6}{2} =0 | *6$
$10-y + 2(3y+8)-3*(y+6)=0$
$10-y+6y+16-3y-18=0$
$2y = -8$
$y = -8/2 = -4$