Question

Представь в виде дроби: a)8/b+6/c b)5/7a-3/7 в)2/x2+3a/5x г)8/xy+9a/2xc

Answer 1

A)$\frac{8}{b} + \frac{6}{c} = \frac{8c}{bc} + \frac{6b}{bc} = \frac{8c+6b}{bc}  b)$$\frac{5}{7a} - \frac{3}{7} = \frac{5-3a}{7a}$ 
 в)$\frac{2}{x^{2} } + \frac{3a}{5x} = \frac{10}{5 x^{2} } + \frac{3ax}{5 x^{2} } = \frac{10+3ax}{5 x^{2} }$
г)$\frac{8}{xy} + \frac{9a}{2xc} = \frac{16xc}{2 x^{2} cy} + \frac{9axy}{2 x^{2} cy} = \frac{16xc+9axy}{2 x^{2} cy}$