<span>1)CH3CH2C(CH3)2CH=CH2
2)сh3-сh(ch3)-сh(c2h5)-сh2-сh2-сh3
3)</span><span>ch = - c-ch-ch2-ch3
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сн3 -с = с-сн2-сн3
I I
ch3 ch3<span>
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1) 2Na + s = na2s
2na + 2 hci = 2 naci + h2
2ha + h20 = 2najh + h2
2na + h2 = 2 nah
2)caco3
caco3
ca3
3)ai203 + 6 hci = 2aici3
ai203 + 2naoh + 3h20 = 2na(ai(oh)4)
ai(oh)3 + hcl = aici3 + 3h20
ai(oh)3 + naon = na(ai(oh)4)
это всё
W(Zn)=0,4757
w(O)=0,2328
w(Ca)=1-{w(Zn)+w(O)}=0,2915
CaxZnyOz
молярная масса вещества
M(CaxZnyOz)=40x+65y+16z
массовые доли элементов
w(Ca)=xM(Ca)/M(CaxZnyOz)
w(Zn)=yM(Zn)/M(CaxZnyOz)
w(O)=zM(O)/M(CaxZnyOz)
система уравнений
40x/{40x+65y+16z}=0,2915
65y/{40x+65y+16z}=0,4757
16z/{40x+65y+16z}=0,2328
решаем...
x=1
y=1
z=2
ZnO + CaO (t)= CaZnO₂ цинкат кальция
2NaOH+CuSO4=Na2SO4(сульфат натрия)+Сu(OH)2
Тип реакции замещение
<span>1)BaO+H2SO4=</span><span> BaSO4+Н2О</span>
<span><span>BaO+SO2=</span><span>BaSO3</span></span>
<span><span><span>BaO+H2O=</span><span>Ba(OН)2</span></span></span>
BaO+Al=р. не идет
2) H3PO4+Cl2O=р.не идет
2H3PO4+2Al=2AlPO4+3H2
<span><span><span><span>2KOH+H2SO4=</span><span>K2SO4+Н2О</span></span></span></span>
<span><span><span><span><span>2KOH+SO2=<span>K2SO3+Н2О</span></span></span></span></span></span>
<em>K</em><em>O</em><em>H</em>
(разб.) + <u>6</u><em>H</em>2<em>O</em> =
[<em>K</em>(<em>H</em>2<em>O</em>)6]<em>O</em><em>H</em><u>2</u><em>K</em><em>O</em><em>H</em>
(конц.) + <u>6</u><em>H</em>2<em>O</em>
(гор) + <u>2</u><em>Al</em> = <u>2</u><em>K</em>
[<em>Al</em>(<em>O</em><em>H</em>)4] + <u>3</u><em>H</em>2↑
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